-16t^2+32t=16

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Solution for -16t^2+32t=16 equation: 



-16t^2+32t=16

We move all terms to the left:

-16t^2+32t-(16)=0

a = -16; b = 32; c = -16;
Δ = b2-4ac
Δ = 322-4·(-16)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-32}{-32}=1$

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